Monday, February 29, 2016

CCNAv2 Completed Packet Tracer 6.3.3.6 A & B w/ DOC/PDF

Hello, and welcome to my blog for CCNA.
Please read all of the text before downloading.

Packet tracer is now ready for download. 
CAVEAT: The PT is not the same as others you may open, read below.
Anyways, here's the download. PLEASE READ BELOW!

6.3.3.6 Packet Tracer VLSM Activity - 172
6.3.3.6 Packet Tracer DOC/PDF Complete - 172

The following addressing tables represent the three possible addressing scenarios the student may get. Note that the Device column is independent of the addressing scheme. For example, a student could receive the device names from Scenario 1 and the addressing scheme from Scenario 3. In addition, the three possible topologies are also independent of the device names and the addressing scheme (click reset in the activity to see the different topologies). Therefore, this activity uses three independent variables with three possible values each for a total of 27 possible combinations (3 device names x 3 addressing schemes x 3 topologies = 27 isomorphs).

Scenario 1 - Network Address: 10.11.48.0/24
Subnet Table
Subnet Description
Number of Hosts Needed
Network Address/CIDR
First Usable Host Address
Last Usable Host Address
Broadcast Address
Host-D LAN
60
10.11.48.0/26
10.11.48.1
10.11.48.62
10.11.48.63
Host-B LAN
30
10.11.48.64/27
10.11.48.65
10.11.48.94
10.11.48.95
Host-A LAN
14
10.11.48.96/28
10.11.48.97
10.11.48.110
10.11.48.111
Host-C LAN
6
10.11.48.112/29
10.11.48.113
10.11.48.118
10.11.48.119
WAN Link
2
10.11.48.120/30
10.11.48.121
10.11.48.122
10.11.48.123

Device
Interface
Address
Subnet Mask
Default Gateway
Building1
G0/0
10.11.48.97
255.255.255.240
N/A
G0/1
10.11.48.65
255.255.255.224
N/A
S0/0/0
10.11.48.121
255.255.255.252
N/A
Building2
G0/0
10.11.48.113
255.255.255.248
N/A
G0/1
10.11.48.1
255.255.255.192
N/A
S0/0/0
10.11.48.122
255.255.255.252
N/A
ASW1
VLAN 1
10.11.48.98
255.255.255.240
10.11.48.97
ASW2
VLAN 1
10.11.48.66
255.255.255.224
10.11.48.65
ASW3
VLAN 1
10.11.48.114
255.255.255.248
10.11.48.113
ASW4
VLAN 1
10.11.48.2
255.255.255.192
10.11.48.1
Host-A
NIC
10.11.48.110
255.255.255.240
10.11.48.97
Host-B
NIC
10.11.48.94
255.255.255.224
10.11.48.65
Host-C
NIC
10.11.48.118
255.255.255.248
10.11.48.113
Host-D
NIC
10.11.48.62
255.255.255.192
10.11.48.1

Building 1
en
conf t
int g0/0
ip add 10.11.48.97 255.255.255.240
no shut
int g0/1
ip add 10.11.48.65 255.255.255.224
no shut
ASW3
en
conf t
int vlan 1
ip add 10.11.48.114 255.255.255.248
no shut
ip def 10.11.48.113
Scenario 2 - Network Address: 172.31.103.0/24
Subnet Table
Subnet Description
Number of Hosts Needed
Network Address/CIDR
First Usable Host Address
Last Usable Host Address
Broadcast Address
PC-A LAN
27
172.31.103.0/27
172.31.103.1
172.31.103.30
172.31.103.31
PC-B LAN
25
172.31.103.32/27
172.31.103.33
172.31.103.62
172.31.103.63
PC-C LAN
14
172.31.103.64/28
172.31.103.65
172.31.103.78
172.31.103.79
PC-D LAN
8
172.31.103.80/28
172.31.103.81
172.31.103.94
172.31.103.95
WAN Link
2
172.31.103.96/30
172.31.103.97
172.31.103.98
172.31.103.99

Device
Interface
Address
Subnet Mask
Default Gateway
Branch1
G0/0
172.31.103.1
255.255.255.224
N/A
G0/1
172.31.103.33
255.255.255.224
N/A
S0/0/0
172.31.103.97
255.255.255.252
N/A
Branch2
G0/0
172.31.103.65
255.255.255.240
N/A
G0/1
172.31.103.81
255.255.255.240
N/A
S0/0/0
172.31.103.98
255.255.255.252
N/A
Room-114
VLAN 1
172.31.103.2
255.255.255.224
172.31.103.1
Room-279
VLAN 1
172.31.103.34
255.255.255.224
172.31.103.33
Room-312
VLAN 1
172.31.103.66
255.255.255.240
172.31.103.65
Room-407
VLAN 1
172.31.103.82
255.255.255.240
172.31.103.81
PC-A
NIC
172.31.103.30
255.255.255.224
172.31.103.1
PC-B
NIC
172.31.103.62
255.255.255.224
172.31.103.33
PC-C
NIC
172.31.103.78
255.255.255.240
172.31.103.65
PC-D
NIC
172.31.103.94
255.255.255.240
172.31.103.81

Branch 1
en
conf t
int g0/0
ip add 172.31.103.1 255.255.255.224
no shut
int g0/1
ip add 172.31.103.33 255.255.255.224
no shut
Room-312
en
conf t
int vlan 1
ip add 172.31.103.66 255.255.255.240
no shut
ip def 172.31.103.65

Scenario 3 - Network Address: 192.168.72.0/24
Subnet Table
Subnet Description
Number of Hosts Needed
Network Address/CIDR
First Usable Host Address
Last Usable Host Address
Broadcast Address
User-4 LAN
58
192.168.72.0/26
192.168.72.1
192.168.72.62
192.168.72.63
User-3 LAN
29
192.168.72.64/27
192.168.72.65
192.168.72.94
192.168.72.95
User-2 LAN
15
192.168.72.96/27
192.168.72.97
192.168.72.126
192.168.72.127
User-1 LAN
7
192.168.72.128/28
192.168.72.129
192.168.72.142
192.168.72.143
WAN Link
2
192.168.72.144/30
192.168.72.145
192.168.72.146
192.168.72.147


Device
Interface
Address
Subnet Mask
Default Gateway
Remote-Site1
G0/0
192.168.72.129
255.255.255.240
N/A
G0/1
192.168.72.97
255.255.255.224
N/A
S0/0/0
192.168.72.145
255.255.255.252
N/A
Remote-Site2
G0/0
192.168.72.65
255.255.255.224
N/A
G0/1
192.168.72.1
255.255.255.192
N/A
S0/0/0
192.168.72.146
255.255.255.252
N/A
Sw1
VLAN 1
192.168.72.130
255.255.255.240
192.168.72.129
Sw2
VLAN 1
192.168.72.98
255.255.255.224
192.168.72.97
Sw3
VLAN 1
192.168.72.66
255.255.255.224
192.168.72.65
Sw4
VLAN 1
192.168.72.2
255.255.255.192
192.168.72.1
User-1
NIC
192.168.72.142
255.255.255.240
192.168.72.129
User-2
NIC
192.168.72.126
255.255.255.224
192.168.72.97
User-3
NIC
192.168.72.94
255.255.255.224
192.168.72.65
User-4
NIC
192.168.72.62
255.255.255.192
192.168.72.1

Remote-Site1
en
conf t
int g0/0
ip add 192.168.72.129 255.255.255.240
no shut
int g0/1
ip add 192.168.72.97 255.255.255.224
no shut
Sw-3
en
conf t
int vlan 1
ip add 192.168.72.66 255.255.255.224
no shut
ip def 192.168.72.65


NOTES:
CIDR:  classless interdomain routing
VLSM: variable length subnet masks



Classes D & E aren't really important (Not important as A-C!)
You should understand these charts, they're helpful.

A small subnetting example: 
IP: 193.10.5.0/24
Take that and turn it into four even networks.

Explained Steps for Subnetting
EVENLY SPACED EXAMPLE
You first need to know how many hosts you're going to put on each network. You first need to find out how many hosts that are on the network. This IP has a "/24", giving you 256 addresses. Refer to the subnetting cheat-sheat on the CCNA2 pane if you don't know. You then divide this by four, because you want to have four even networks.

You'll get four addresses...
a. 193.10.5.0
b. 193.10.5.64
c. 193.10.5.128
c. 193.10.5.192

So these are our network addresses for our four evenly spaced networks, but now we need our subnet mask!
So, two to WHAT power gives you 64? Answer is 6. So if 2^6 = 64, that is "32-6", which equals 26. Meaning your subnet mask equals "/26", as they are all evenly spaced.

Well, person on the internet, what if they're NOT evenly spaced?
Good question. It's relatively simple, sort of like the first example.
So lets give ourselves an example.

We want one network with  1-120, another with 1-42, and another with 3-2. 
The IP address given is what we had prior to this one; 193.10.5.0/24

So where do we start? 
We start with the largest number, which is 120. So 120 means we will have HOW MANY hosts?
128, because we go to the next highest power of two, so with that, what is 2^x=128? x = 7.

So for 1-42, it's 64 = 2^6.
So forth.

So network addresses...
193.10.5.0/25
193.10.5.128/26
193.10.5.192/30
193.10.5.196/30
193.10.5.200/30

Anyways, that's a simple guide to subnets. If you need an idea or more in-depth explanations, visit here. http://www.ralphb.net/IPSubnet/index.html

Below are the commands if you don't want to download.

2 comments:

  1. this version is not compatible with my schools version of pt. plz fix it asap. ty

    ReplyDelete
    Replies
    1. That is not an issue on our end. I can happily provide the configurations though. Here is the device configurations for most/all devices. http://pastebin.com/3LeXU0uT

      Delete

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